20x+1-x^2=-5-x^2-3x

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Solution for 20x+1-x^2=-5-x^2-3x equation: 



20x+1-x^2=-5-x^2-3x

We move all terms to the left:

20x+1-x^2-(-5-x^2-3x)=0

We add all the numbers together, and all the variables

-1x^2-(-5-x^2-3x)+20x+1=0

We get rid of parentheses

-1x^2+x^2+3x+20x+5+1=0

We add all the numbers together, and all the variables

23x+6=0

We move all terms containing x to the left, all other terms to the right

23x=-6

x=-6/23

x=-6/23

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